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| residency2009 Total Posts: 25 | Posted: Wed Nov 05, 2008 01:07 pm Hi, Can anybody help me out please... At t=0, there are 6 x 1023 radioactive atoms of a substance, which decay with a disintegration constant (lambda) equal to 0.01/sec. What would be the initial decay rate ? A) 6 x 1023 (10 to the power of 23, 22, 21 and 20) B) 6 x 1022 C) 6 x 1021 D) 6 x 1020 Answer given is C |
| superbdoc Total Posts: 273 | Posted: Wed Nov 05, 2008 04:30 pm GO to this site....steps are explained easily here https://hyperphysics.phy-astr.gsu.edu/hbase/nuclear/halfli2.html |
| RABIES Total Posts: 42 | Posted: Wed Nov 05, 2008 04:45 pm A=LAMBDA*N(LAMBDA IS DECAY CONSTANT AND N TOTAL NUMBER OF THE SUBSTANCE) .01* 6 x 10 23 =6X 10 21 |